Как в SQL Server сгенерировать оператор CREATE TABLE для данной таблицы?

Вот сценарий, который я придумал. Он sql-srever обрабатывает столбцы Identity, значения dynamic-sql по умолчанию и первичные sql-server ключи. Он не обрабатывает sql-srever внешние ключи, индексы, триггеры sql-srever и прочие умные штуки. Работает dynamic-sql на SQLServer 2000, 2005 и scripting 2008.

declare @schema varchar(100), @table varchar(100)
set @schema = 'dbo' -- set schema name here
set @table = 'MyTable' -- set table name here
declare @sql table(s varchar(1000), id int identity)

-- create statement
insert into  @sql(s) values ('create table [' + @table + '] (')

-- column list
insert into @sql(s)
select 
    '  ['+column_name+'] ' + 
    data_type + coalesce('('+cast(character_maximum_length as varchar)+')','') + ' ' +
    case when exists ( 
        select id from syscolumns
        where object_name(id)=@table
        and name=column_name
        and columnproperty(id,name,'IsIdentity') = 1 
    ) then
        'IDENTITY(' + 
        cast(ident_seed(@table) as varchar) + ',' + 
        cast(ident_incr(@table) as varchar) + ')'
    else ''
    end + ' ' +
    ( case when IS_NULLABLE = 'No' then 'NOT ' else '' end ) + 'NULL ' + 
    coalesce('DEFAULT '+COLUMN_DEFAULT,'') + ','

 from INFORMATION_SCHEMA.COLUMNS where table_name = @table AND table_schema = @schema
 order by ordinal_position

-- primary key
declare @pkname varchar(100)
select @pkname = constraint_name from INFORMATION_SCHEMA.TABLE_CONSTRAINTS
where table_name = @table and constraint_type='PRIMARY KEY'

if ( @pkname is not null ) begin
    insert into @sql(s) values('  PRIMARY KEY (')
    insert into @sql(s)
        select '   ['+COLUMN_NAME+'],' from INFORMATION_SCHEMA.KEY_COLUMN_USAGE
        where constraint_name = @pkname
        order by ordinal_position
    -- remove trailing comma
    update @sql set s=left(s,len(s)-1) where id=@@identity
    insert into @sql(s) values ('  )')
end
else begin
    -- remove trailing comma
    update @sql set s=left(s,len(s)-1) where id=@@identity
end

-- closing bracket
insert into @sql(s) values( ')' )

-- result!
select s from @sql order by id